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What is the solution to the equation sqrt2x + 8 − 6 = 4
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|dw:1379901401731:dw|
move all numbers on one side - so subtract 2 from each side
square both sides in order to remove the sqrt sign now solve for x
\[\eqalign{ &\sqrt{2x}+8-6=4 \\ &\sqrt{2x}+2=4 \\ &\sqrt{2x}=4-2 \\ &\sqrt{2x}=2 \\ &\sqrt{2x}^2=2^2 \\ &2x=4 \\ &x=4/2=2 }\]
i think X= 2
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That is why its good to not just give answers - we should be explaining not providing answers
i accidentally made a typo. the sqrt is over 2x+8 and not just 2x. i'm sorry.
1. Add 6 to both sides 2. Square both sides 3. Subtract 8 from both sides. 4. Divide both sides by 2 5. Check your answer.
@JuanitaM can you please help
|dw:1379966493525:dw|
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