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Mathematics 19 Online
OpenStudy (anonymous):

I need to find the angles of a right triangle with only 2 side lengths: 4 and 5.6 How would I find the angles?

OpenStudy (anonymous):

Trigonemtry would help you with this. Sin(theta) = opposite side/hypotenuse, Cos(theta) = adjacent side/hypotenuse and tan(theta) = opposite/adjacent. You can use the inverse functions (equivalent to dividing across by the function) to find the angles. Say you had the opposite and the adjacent, you would say theta = tan^(-1) opposite/adjacent

OpenStudy (anonymous):

So I would need to divide my opposite and adjacent then multiply by cotangent?

OpenStudy (anonymous):

You would take the cotangent of the opposite divided by the adjacent. You can't multiply by cotangent as it is not a number in itself

OpenStudy (anonymous):

In this case, my triangle is a 45 45 90, and it is opposite over hypotenuse, would I do Sin or cosine?

OpenStudy (anonymous):

SOH CAH TOA, Sin involves Opposite and Hypotenuse, Cosine involves Adjacent and Hypotenuse, and Tangent involves Opposite and Adjacent.

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