I need to find the angles of a right triangle with only 2 side lengths: 4 and 5.6 How would I find the angles?
Trigonemtry would help you with this. Sin(theta) = opposite side/hypotenuse, Cos(theta) = adjacent side/hypotenuse and tan(theta) = opposite/adjacent. You can use the inverse functions (equivalent to dividing across by the function) to find the angles. Say you had the opposite and the adjacent, you would say theta = tan^(-1) opposite/adjacent
So I would need to divide my opposite and adjacent then multiply by cotangent?
You would take the cotangent of the opposite divided by the adjacent. You can't multiply by cotangent as it is not a number in itself
In this case, my triangle is a 45 45 90, and it is opposite over hypotenuse, would I do Sin or cosine?
SOH CAH TOA, Sin involves Opposite and Hypotenuse, Cosine involves Adjacent and Hypotenuse, and Tangent involves Opposite and Adjacent.
Join our real-time social learning platform and learn together with your friends!