Question

Find y'=(cscx+cotx)^-1

Answer 1

@jim_thompson5910

Answer 2

@ganeshie8

Answer 3

I used chain rule and got csc/csc+cotx is that correct?

Answer 4

I checked in wolfram and it's listed as an implicit derivative so I'm assuming it's right.

Answer 5

I don't understand the question, you give y' =.... find y? or y =... find y'?

Answer 6

Sorry, it's y. We're solving for y'

Answer 7

http://www.wolframalpha.com/input/?i=y%3D%28cscx%2Bcotx%29%5E-1

Answer 8

I don't know why , "my" wolfram says different from yours, here http://www.wolframalpha.com/input/?i=%28%28csc+x+%2Bcot+x%29^%28-1%29%29%27

Answer 9

Oh, I typed in y and looked for y' in wolfram. I didn't know we can just type in y'. Thanks.