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Geometry 7 Online
OpenStudy (anonymous):

A ladder leaning against a wall makes a 60° angle with the ground. The base of the ladder is 4m from the building. How high above the ground is the top of the ladder?

OpenStudy (zale101):

we are dealing with a 30-60-90 right triangle here

OpenStudy (anonymous):

yes. so can i just set it up and solve like i normally would for this kind of special triangle?

OpenStudy (zale101):

based off of what is told, can u draw the figure?

OpenStudy (anonymous):

|dw:1379909995272:dw|

OpenStudy (anonymous):

is that right?o:

OpenStudy (anonymous):

so how can i solve for the height with what i have here?

OpenStudy (zale101):

Base = 4m Angle with ground = 60 degrees Height of top of ladder is found by tan = Opposite/Adjacent

OpenStudy (zale101):

tan (60) = Opposite/4

OpenStudy (anonymous):

what is tan? how is the height found using that?o:

OpenStudy (zale101):

you don't know what's tangent ?

OpenStudy (anonymous):

no i don't. x:

OpenStudy (zale101):

In a right triangle, the tangent of an angle is the length of the opposite side divided by the length of the adjacent side. http://www.mathopenref.com/trigtangent.html

OpenStudy (zale101):

|dw:1379910337028:dw|

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