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Integrate -∫cosech(x)coth(x) dx
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csch(x). This is just an identity you need to know. It is the same as the -∫csc(x)cot(x) dx but in hyperbolic form.
u sure ?
well, +C.
so if i have ∫ how would u solve that
\[\int\limits_{}^{}\frac{ \cosh(x) }{ 9-Sinh^2(x)}\]
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can u help ?
I'd imagine you would be doing some sort of integration by parts or partial fractions, but I really don't know. Sorry.
\[\int\frac{\cosh x}{9-\sinh^2x}~dx\] Substitute \(u=\sinh x\), so \(du=\cosh x~dx\): \[\int\frac{du}{9-u^2}\] Then partial fractions or trig sub should work.
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