Question

find the limit as x -> -2
(x^2+1)/(3x^2-2x+5)

Answer 1

replace \(x\) by \(-2\) and see what you get

Answer 2

i got like -1/7? i just don't know if it's right :(

Answer 3

\((-2)^2+1=4+1=5\) for the numerator

Answer 4

\[3(-2)^2-2\times (-1)+5\] is your denominator
i doubt you get \(-\frac{1}{7}\)

Answer 5

5/21?

Answer 6

:)

Answer 7

in fact if my arithmetic is correct, the denominator is \(19\) making the limit \(\frac{5}{19}\)

Answer 8

course my arithmetic could be wrong

Answer 9

check it

Answer 10

isnt the equation 2x -2?

Answer 11

lol you are right, i am wrong

Answer 12

not 2x -1?

Answer 13

yeah i made a stupid mistake
you are correct \(\frac{5}{21}\)

Answer 14

es otay, (: do you know how to find a fourth root on a calculator? o: :(

Answer 15

depends on the calculator
you could find the square root twice if it is not a fancy one

Answer 16

or just use this
http://www.wolframalpha.com/input/?i=fourth+root%2816%29

Answer 17

ti-84? o:

Answer 18

i don't really use calculators when i am on line
wolfram does it all, and is very very easy to use
see the link i sent