find the limit as x - -2
(x^2+1)/(3x^2-2x+5)

Question

find the limit as x -> -2
(x^2+1)/(3x^2-2x+5)

anonymous · Answer

replace $x$ by $-2$ and see what you get

anonymous · Answer

i got like -1/7? i just don't know if it's right :(

anonymous · Answer

$(-2)^2+1=4+1=5$ for the numerator

anonymous · Answer

$$3(-2)^2-2\times (-1)+5$$ is your denominator
i doubt you get $-\frac{1}{7}$

anonymous · Answer

5/21?

anonymous · Answer

:)

anonymous · Answer

in fact if my arithmetic is correct, the denominator is $19$ making the limit $\frac{5}{19}$

anonymous · Answer

course my arithmetic could be wrong

anonymous · Answer

check it

anonymous · Answer

isnt the equation 2x -2?

anonymous · Answer

lol you are right, i am wrong

anonymous · Answer

not 2x -1?

anonymous · Answer

yeah i made a stupid mistake
you are correct $\frac{5}{21}$

anonymous · Answer

es otay, (: do you know how to find a fourth root on a calculator? o: :(

anonymous · Answer

depends on the calculator
you could find the square root twice if it is not a fancy one

anonymous · Answer

anonymous · Answer

ti-84? o:

anonymous · Answer

i don't really use calculators when i am on line
wolfram does it all, and is very very easy to use
see the link i sent