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Mathematics 17 Online
OpenStudy (anonymous):

cos2a = ???

OpenStudy (anonymous):

I am sorry I dont know.

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

cos(2a)="any value between -1 and +1"

OpenStudy (john_es):

\[cos (2a)=\cos^2(a)-\sin^2(a)\]

OpenStudy (cwrw238):

pther identities are cos(2a)=2cos^2(a)− 1 and cos(2a)=1−2sin^2(a)

OpenStudy (anonymous):

Oh, is about identities?\[\cos(2a)=\frac{ e^{i2a}+e^{-i2a} }{ 2 }\]is a good one

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