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5^3x=29
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Solve the following equation
This is a tough one.... Lol
It using logarithmic form I just can't solve it
What grade are u in?
Trig
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oh
May be using, \[\log(a^n)=b\Rightarrow n\log( a)=b\]
Log[5]29/3=x
I guess that's the answer
I suppose you have, \[5^{3x}=29\] right or not?
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Yes
Then you must apply the log function to both sides, not only the 5 in the left side.
Sorry It was my mistake.
The formula I should give you is, \[\log(a^n)=b\Rightarrow n\log(a)=\log (b)\] I forget to put the log in the right side.
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