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Mathematics 8 Online
OpenStudy (anonymous):

5^3x=29

OpenStudy (anonymous):

Solve the following equation

OpenStudy (anonymous):

This is a tough one.... Lol

OpenStudy (anonymous):

It using logarithmic form I just can't solve it

OpenStudy (anonymous):

What grade are u in?

OpenStudy (anonymous):

Trig

OpenStudy (anonymous):

oh

OpenStudy (john_es):

May be using, \[\log(a^n)=b\Rightarrow n\log( a)=b\]

OpenStudy (anonymous):

Log[5]29/3=x

OpenStudy (anonymous):

I guess that's the answer

OpenStudy (john_es):

I suppose you have, \[5^{3x}=29\] right or not?

OpenStudy (anonymous):

Yes

OpenStudy (john_es):

Then you must apply the log function to both sides, not only the 5 in the left side.

OpenStudy (john_es):

Sorry It was my mistake.

OpenStudy (john_es):

The formula I should give you is, \[\log(a^n)=b\Rightarrow n\log(a)=\log (b)\] I forget to put the log in the right side.

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