Question

I need help. Here is an example from the book f(x)=16t^2+48t+8
So far I have the y intercept: (0,8) the domain: all real numbers and the minimum y=-28 @ x=1.5
I need someone to explain to me how to find the vertex, axis of symmetry, x intercept, and the range. Thanks!

Answer 1

how did you find the y-intercept?

Answer 2

My teacher told us it is the last number in the equation always.

Answer 3

Also that is what my graphing calculator said @jdoe0001

Answer 4

hmm... well... how did you get it from the calculator? I mean... what did you do?

Answer 5

It has a thing that will tell you the y intercept if you enter the equation

Answer 6

anyhow, to get the y-intercept, set x = 0, and solve for "y"

anyhow, to get the x-intercept, set y = 0, and solve for "x"

Answer 7

Can you show me. For the x. I know how to solve to find the y but don't understand how to get the x. S(t)=16t^2+48t+8

Answer 8

hmm, well
to get the y-intercept, set t = 0, and solve for "y"

to get the t-intercept, set y = 0, and solve for "t"