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Mathematics 18 Online
OpenStudy (waheguru):

What would be the restrictions to this x+1/5x-4?

OpenStudy (anonymous):

what will make the denominator go to zero? 5x-4 = 0 solve for x

OpenStudy (waheguru):

@JuanitaM Does it matter if the numerator is zero or not?

OpenStudy (waheguru):

4/5 will make x =0 but should I also find what number makes numerator zerp sp x does not equal -1

OpenStudy (anonymous):

not for restrictions normally, but I have seen it if they ask for range... no just stick with denominator.

OpenStudy (waheguru):

so 4/5 right?

OpenStudy (waheguru):

and also I have another question x-3/x+2 What would be the restriction for this?

OpenStudy (waheguru):

My text book says -2 and 1 but I am confused why?

OpenStudy (anonymous):

yes 4/5

OpenStudy (anonymous):

set denominator to zero and solve for x...the answer is right

OpenStudy (waheguru):

but how 1?

OpenStudy (anonymous):

x + 2 = 0 x + 2 -2 = 0 -2 x = -2

OpenStudy (waheguru):

yea I got that but i did not get 1

OpenStudy (waheguru):

the textbook is wrong for that right?

OpenStudy (anonymous):

|dw:1380066317035:dw| is the problem written like that?

OpenStudy (waheguru):

|dw:1380066384838:dw|

OpenStudy (waheguru):

|dw:1380066420396:dw|

OpenStudy (waheguru):

But then how can 1 be a restriction?

OpenStudy (anonymous):

ahh...different than what you typed. yes you must set both to equal zero in the denominator

OpenStudy (anonymous):

remember, restrictions are from ORIGINIAL problem not your simplified one

OpenStudy (waheguru):

hmm, but in some case we can simplify right?

OpenStudy (anonymous):

you must simplify always but restrictions are ONLY based on original problem

OpenStudy (waheguru):

that makes sense

OpenStudy (waheguru):

thanks!

OpenStudy (anonymous):

Great!

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