What would be the restrictions to this x+1/5x-4?
what will make the denominator go to zero? 5x-4 = 0 solve for x
@JuanitaM Does it matter if the numerator is zero or not?
4/5 will make x =0 but should I also find what number makes numerator zerp sp x does not equal -1
not for restrictions normally, but I have seen it if they ask for range... no just stick with denominator.
so 4/5 right?
and also I have another question x-3/x+2 What would be the restriction for this?
My text book says -2 and 1 but I am confused why?
yes 4/5
set denominator to zero and solve for x...the answer is right
but how 1?
x + 2 = 0 x + 2 -2 = 0 -2 x = -2
yea I got that but i did not get 1
the textbook is wrong for that right?
|dw:1380066317035:dw| is the problem written like that?
|dw:1380066384838:dw|
|dw:1380066420396:dw|
But then how can 1 be a restriction?
ahh...different than what you typed. yes you must set both to equal zero in the denominator
remember, restrictions are from ORIGINIAL problem not your simplified one
hmm, but in some case we can simplify right?
you must simplify always but restrictions are ONLY based on original problem
that makes sense
thanks!
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