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if g(x) =1+x+x^2, find g'(1) and the equation of the tangent line to y=g(x) at the point (1,3). (evaluate limit her do not use approximation)
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Do you know how to find g'(x)? You'll need that first.
do you find derivative?
Yes
Once you get g'(x), you want g'(1) so plug in x=1
Then g'(1) is your slope, m, in the tangent line y=mx+b. Then just plug in the point the tangent line passes through (1, 3) to find b.
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so i got y=3x
Looks good. Good job.
phew. . . trying to do homework on a subject that has not been taught is difficult
Yea...i can imagine :/
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