Question

proof, need help getting started

Answer 1

if a,b,c are real numbers,a does not =0, b< 0 and b/2 < sqrt(ac), then the quadratic equation ax^2+bx+c=o has no real solution.

Answer 2

The discriminant is:

\(b^2 - 4ac\)

If the discriminant is negative, there is no real solution.

The discriminant is negative if the inequality \(b^2 - 4ac < 0 \) is true.

\(b^2 - 4ac < 0\)

\(b^2 < 4ac\)

Divide both sides by 4:

\( \dfrac{b^2}{4} < ac \)

If \(\dfrac{b}{2} < \sqrt{ac}\) there is no solution.

Answer 3

^there is no _real_ solution