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Mathematics
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Algebra
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in this case, treat the imaginary number "i" as a variable and then combine like terms
@ganeshie8 can you help explain it to me?
we do exactly as completeidiot said above
\(\large (1+3i) + (2-5i) \)
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combine 1 and 2 combine 3i and -5i
1 and 2 = 3 3i and -5i = -2
dont ignore i, thats sticking to numbers :)
1 and 2 = 3 3i and -5i = -2i
okay so it's 3- 2i
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perfect !!! \(\large (1+3i) + (2-5i) \) \(\large 1+3i + 2-5i \) \(\large 1+ 2 + 3i-5i \) \(\large 3-2i \)
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