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given the equation 5x-3y=15, how would you graph the line USING the x and y int.?
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would u just simply put a point on -3 and go up 5 and run 1?
5x-3y=15 To find y-int. plug in x=0, solve for y To find x-int: plug in y=0, solve for x
Once you do that, it's easy to graph.
thanks!!!
wait
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it just said to graph 5x-3y=15 by using the x and y int. so i just write 5(3)-3(5)=15?
.-.
No. Do exactly as i said above FIRST.
OH! so x=3 and y=5?
x-int is correct, y isn't.
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isnt y correct because its : 5(0)-3y=15
ohhhhh its -5
now you have your x and y intercepts. Use them to plot the graph.
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