Question

A terrorist shoots at a police. The probability of bullet not hitting the police is 0.4. The probability of police dying after hitting the bullet is 0.6. What is the probability of the polic not dying after a shot?

Answer 1

"The probability of police dying after hitting the bullet is 0.6."
so if terrorist=1, then police life=0.4

"The probability of bullet not hitting the police is 0.4"
so terrorist=0.6

0.6 x 0.4 = 0.24

Answer 2

24% chance of survival if terrorist shoots at police

Answer 3

no 0.64

Answer 4

see before hit 0.4 -after hit 0.6=0.2

Answer 5

0.6-0.4=0.2
not hit=0.4+0.2=0.6 i got that ans but answer is 0.64

Answer 6

the probability of police surviving is a subset of being hit
that's why I multiplied them

Answer 7

ahhhh

Answer 8

you're right:
when the terrorist doesn't even hit them, that's another way to survive

Answer 9

they can survive after being hit (0.24)
or they can survive by not being hit (0.4)

Answer 10

0.24+0.4=0.64 right

Answer 11

yes, my first post calculates the chance of the police surviving
with the 60% chance of being hit

of course you have to give police another relief if the
40% of terrorist missing occur