i need help with these problems for my homework step by step 3x^2-x+4x 24x^2=-10x+4 (x-5)(x+4)=2(x-5) 9x^-2x+4=10x
What do you need to do? Solve for x?
i have to factor them out
but im not sure of where to start
How have you been taught to factor them? Have you learned the quadratic equation yet?
A quick way to check your work would be to plug each "part" or "piece" into a graphing calculator and find the zeros/interceptions.
i havent been taught yet i was absent last class
For 3x^2-x+4x can you combine any terms?
i dont have a graphing calculator, we're not allowed to use them in class
no you dont combine like terms
It might help to factor, but what are you suppose to do?
i dont know what to do thats the problem
How about you combine the x terms? 3x^2-x+4x
i think the formula is ax^2+bx+c=0
3x^2-x+4x=3x^2 + (4x-x)=?
0 ?
what is 4x-x=?
4
No, you can factor out the x for x(4-1), what is 4-1?
3
yes, so 3x^2-x+4x= 3x^2+(4x-x)=3x^2+3 now can you factor anything else out?
im not sure
How about the 3? 3x^2+3=3(x^2+1)
im lost honestly
Okay Do you understand how to factor things out of equations?
yes
If you add, subtract, divide or multiply on one side of an equation you have to do the same on the other side. Sound familiar?
So x^2+2x=-1 would look like what if you added 1 to both sides?
Let's do (x-5)(x+4)=2(x-5) What if we divide both sides by (x-5)?
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