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How can I find all the value of sin(3θ)=(1/2) in the interval [0, 2pi]
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Well, first, what angles do you know have a sine of 1/2?
pi/6 and (2pi)/3
\[\large \frac{2\pi }{3}\]? I don't think so :P
Blah, I meant to say (5pi)/6
I know that there is supposed to be 6 values of θ, I just don't know how to get to that point.
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Okay, then think of six angles whose sines are all 1/2. Crucial thing is not to confine yourself in \(\large [0,2\pi]\) but rather, triple that... into \[\Large [0,6\pi]\] and see what we get
OH! pi/6, (5pi)/6, (13pi)/6, (17pi)/6, (25pi)/6, (29pi)/6
I then take all these divide by three
So my final answers would be pi/18, (5pi)/18, (13pi)/18, (17pi)/18, (25pi)/18, (29pi)/18
Are those correct?
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