Question

solution for x2-2x=6?

Answer 1

\[x^2-2x=6\] is this it?

Answer 2

yes! i need the solution or solutions

Answer 3

ok so you are gonna bring over your 6
\[x^2 -2x-6=0\]

looking at this i think we have to use the quadratic formula. Do you know how?

Answer 4

not really good, i'm working on it

Answer 5

Thats alright I am here to help :)
so remember this
\[ax^2 +bx+c\]

\[\frac{ -b \sqrt{b^2 -4ac} }{ 2a }\]

plugging in what we have makes it

\[\frac{ -(-2)\sqrt{(-2)^2-4(1)(-6)} }{ 2(1)}\]

Answer 6

opps i made a mistake there should be a + and - between (-b) and the square root

Answer 7

so \[\frac{ 2\pm \sqrt{28} }{ 2 }\]
so breaking it up \[\frac{ 2+2\sqrt{7} }{ 2}\] \[\frac{ 2-2\sqrt{7} }{ 2}\]
because there is a 2 in front and a 2 in front of the radical it can be divided by the 2 on the bottom
making them \[1+\sqrt{7}\] and \[1-\sqrt{7}\]

Does this make sense?