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how do you write an equation of the line with the slope of -2 and containing the point (2,-4)?
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A line in slope-intercept form looks like this... y = mx + b We are given the slope. -2 Now, it looks like this... y = -2x + b We are given a point. (2,-4). What do you suppose we could do with that information?
well i know that is going to be the y intercept and it the point was (0,-4) the y intercept would be -4 but since there is now a 2 instead of a 0 i have no idea what to do.
Not bad. Just substitute, anyway. y = -2x + b (2,-4) suggests x = 2 when y = -4, so -4 = -2(2) + b And we should be able to solve this for 'b'. No?
so b would equal 0?
Looks like it. Good work.
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hey thanks i appreciate it!
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