The function b(x) = 2x − 5 determines how many bags of dog food need to be purchased for an animal shelter, where x is the number of dogs at the shelter. The shelter manager uses m(b(x)) to find the amount of money to bring for the dog food purchase. The function m(x) = 3x + 1. Solve for how much money to bring when there are 10 dogs in the shelter. 15 31 46 52
write down the given functions
# of bags required :- b(x) = 2x − 5 amount of money required for x bags:- m(x) = 3x + 1
amount of money required for x dogs :- m(b(x))
so we would insert 10 into the equation in place of x because there is 10 dogs?
yup, you have 3 functions, whuch function gives u money, if u insert # of dogs ?
last 1
m(x) = 3x + 1
m(x) = 3x + 1 gives u money, if u enter # OF BAGS
so we need to use m(b(x)) = 3x + 1?
but we dont ahve # of bags, we just have # of dogs
we need to use :- m(b(x))
put x = 10 m(b(10))
find b(10) first
b(x) = 2x − 5 b(10) = 2(10) − 5 = 15 put this in m(b(10))
m(b(10)) m(15)
find m(15) now
m(x) = 3x + 1 m(15) = ?
u wid me still ? :)
yeah I gotcha
m(15) = 3(15) + 1 45+1 m(15) = 46
good job !
so they need 46 dollars for dog food :)
yup ! u like dogs... ur dp says it
lol
my picture is my dog :)
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