Evaluate f(x) = x 2 + 1 for f(-1). a.0 b.undefined c.2
Do this the same way you did it before. X=1...put -1 in for x in that problem
(-1)*2+1
or also written it is 2(-1) + 1
f(x) = x^2 + 1 f(-1)= (-1)^2 + 1 = 1 + 1 = ?
Hold on? Is that a square root? Be sure to write that out next time
Well done @Hero
Its \(f(x) = x^2 + 1\) Sometimes when students copy and paste, they forget to add the caret.
ok so the answer is 2 thanks a lot
Yes, I should have picked up on that.
can you guys help me with one more its Evaluate f(x) = x^ 2 + 1 for f(10). a.2√2 b.101 c.21
f(x) = x^2 + 1 f(10) = (10)^2 + 1 = 100 + 1 = ?
what about this one? If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] 2. a.1 b.2 c.9
I thought you said you only had one more....You tricked me :)
sorry...lol this is the last one.
f(2) - g(1) = (2)^2 + 1 -(3(1) + 1) = 4 + 1 - 3 - 1 = 5 - 4 = ?
thanks
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