Question

How do I solve this? (Transforming formulas)

ab-5=b/3 solve for b

Answer 1

Okay, I'll try to show you

Answer 2

Ok thank u

Answer 3

\[
\begin{split}
ab-5&=&\frac b3 \\
3(ab-5)&=&b \\
3ab-15&=&b \\
\end{split}
\]This is the first step.

Answer 4

Alright

Answer 5

\[
\begin{split}
3ab-15 &=& b \\
-15 &=& b-3ab \\
-15 &=& b(1-3a)
\end{split}
\]This is the next step

Answer 6

\[
b = -\frac{15}{1-3a}
\]This is the final result

Answer 7

I'll explain the strategy I used:

1) I got rid of the factions
2) I got all terms with \(b\) on the same side, and all terms without \(b\) on other side.
3) I factored out \(b\)
4) I divided by the factor to isolate \(b\)

Answer 8

Thank you so much it was very helpful