Solve for x: -2/3x+1/5x=2 A. -1/ 10 B. -7/ 30 C. -4/ 15 D. 13/ 30 E. None of the above
Im so confused because the answer should be -7/30 or -30/7
I get -30/7
did you get that by using the reciprocal?
\[-\frac{ 2 }{ 3 }x+\frac{ 1 }{ 5 }x=2\] \[-\frac{ 10 }{ 15}x+\frac{ 3 }{ 15}x=2\] becomes \[-\frac{ 7 }{ 15 }x=2\] \[x=2*-\frac{ 15 }{ 7 }\] \[x=-\frac{ 30 }{ 7 }\]
if you plug that in for x it does not equal 2.-7/30 will equal 2
the x is in the denominator
I did the math and got 2
are you using an calculator? if so make sure you use ()
a*
n. How would -30/7 if you have negative 7 over 15x equals two.
I don't have -7 over 15. I have -15 over 7
in this problem the x is in the denominator. And I am not sure how to isolate x
Are you sure the x is in the denom and not being multiplied by the whole fraction?
can you use the equation tab below the chat box to type in the equation exactly the way it look in the book.
yes and that is what has me stuck. is proper \[\frac{ -3 }{3x }+\frac{ 1 }{ 5x }=2\]
oh okay.
-2/3x
is it -3/3x or -2/3x?
ok
\[\frac{ -2 }{ 3x }+\frac{ 1 }{ 5x }=2\]
I am sorry. I'm stumped. bump the question and perhaps someone else can help you.
I do not see a way to get -7/30 out of the original equation.
don't you need to multiply 15x by the two also to keep both sides equal
you get -10 +3 = 30x then divide by 30
yes when you multiply 2 by 15x you get 30x then you divide the 30
thank you
okay, im glad you got it. np
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