The graph of f(x) consists of 14 points. Six of the points lie in Quadrant I of the coordinate plane.
I know it can't be six, because six would be the answer for an even function. Therefore, I'm almost certain it's eight. I just need a second opinion.
Im not sure how all the point stuff works, but an odd function means it's symmetrical about the origin. So.....I would THINK that if there are 6 in quadrant one then there would be 6 in quadrant 3 by default.
I was just reading the lesson over and I'm starting to think that too. Either way they'd have the same amount...so trick question I think. Thanks!
Not necessarily. I think you can have one point quadrant 2. If anodd function is symmetric about the origin, you can have 6 in quadrant 1, 6 in quadrant 3 and 1 each in quadrant 2 and 4. |dw:1380481188455:dw|
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