for the quadratic function f(x) = (x - (1/3))62 + 2 in standard form, identify the domain, range, vertex, and axis of symmetry of its graph.
i got domain is all real numbers. vertex: ((1/3), 2); axis of symmetry is x = (1/3)

Question

for the quadratic function f(x) = (x - (1/3))62 + 2 in standard form, identify the domain, range, vertex, and axis of symmetry of its graph.
i got domain is all real numbers. vertex: ((1/3), 2); axis of symmetry is x = (1/3)

anonymous · Answer

range: |dw:1380484623726:dw|

jdoe0001 · Answer

can you see where the vertex is?

anonymous · Answer

the quadratic function is suppose to be f(x) = (x-(1/3))^2 + 2

anonymous · Answer

vertex is (1/3), 2?

jdoe0001 · Answer

yes, and the parabola is going upwards, leading coefficient is positive, so it has a minimum, thus the range is correct $\bf \boldsymbol{ [2, +\infty)}$

anonymous · Answer

Thank you!

jdoe0001 · Answer

the domain will be $\bf x \in \mathbb{R}$

jdoe0001 · Answer

|dw:1380485445151:dw|