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Mathematics 18 Online
OpenStudy (anonymous):

x^6 = 27x^3

OpenStudy (anonymous):

\[ x^6-27x^3 = 0 \\ x^3(x^3-27) = 0 \]

OpenStudy (anonymous):

Whats the solution though ? I got the x3(x3−27)=0 idk what to do after that

OpenStudy (anonymous):

x=?

OpenStudy (anonymous):

Two equations: \[ x^3=0\\ x^3-27=0 \quad \quad x^3=27 \]So there are 2 unique solutions.

OpenStudy (anonymous):

Do I not get rid of the 3 in the x

OpenStudy (anonymous):

Take the cube root \(\sqrt[3]{\quad}\)

OpenStudy (anonymous):

so 0 and 3

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

THanks !

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