Question

Can someone guide me through this?

It says to use special right triangle relationships to find the measure of the value of x and y. Leave answers in radical form.

Answer 1

$$
y\sin(45)=13\\
\sin(45)=\cfrac{\sqrt 2}{2}\\
y=\cfrac{13\times 2}{\sqrt 2}=13\sqrt 2\\
x=y\cos(45)\\
\cos(45)=\cfrac{\sqrt 2}{2}\\
x=13\sqrt 2\times\cfrac{\sqrt 2}{2}=13
$$
http://en.wikipedia.org/wiki/Special_triangles
Let me know if you have any questions.

Answer 2

Oh I see now, thank you!

Answer 3

You're welcome.