Solve the system by graphing? Help?! -3x-y= -10 4x-4y=8
Well, graph them. Slope-Intercept Form is often convenient. Find their intersection.
Is there a formula? @tkhunny
y=mx+b is the formula
how would i plug it in?
rearrange -3x-y=-10 and 4x-4y=8 so that they are in slope intercept form: y=mx+b. do you know how to do it?
No :/
4y=m(4x)+8?
\[-3x-y=-10\] \[-y=3x-10\] \[y=-3x+10\]
how about now?
you do the same thing with; 4x - 4y = 8 -4y = -4x - 8 ; subtract 4x from both sides y= x -2 ; divide -4 from both sides now you are left in slope intercept form y = x - 2
are you able to graph the two? y=-3x+10 y=x-2
hold on im graphing
(3,-1)?
are those the points you got from graphing?
i dont get it
Can you solve the two equations for y or not?
no
What is your plan for graphing them? I have to believe that you are given a "solve by graphing" problem only AFTER you have been given sufficient information to graph the equations.
Take the first equation and add 3x to both sides. What do you get?
Y=-3x+10 all u have to do is make a table. Have x on the top of a sideways ladder tas and y on the bottom. Make 3 sections. Have -1 as x on the first section and the 0 then 1 the for y you just have to plug it in the equation and then graph it. Do the same for the other equation
(-1,3) or (3,1)?
Like for -1 u do -3(-1) which is 3 and thenu add10 which is 13 so your first point is (-1, 13) then do the same for the rest do u get it?
?
@otonoGold u have to have three x points because it doesn't give a specific coordinate so you have to pick the x coordinate except it has to be one negative number one zero then a positive of that same number like I chose -1, 0 and 1
(3,-1) is incorrect
So I see we are guessing now.
Ok so I got 3 coordinates by doing what I told you to do last comment. I have (-1,13) (0,10) and (1,7) for the equation -3x-y=10
The next equation is 4x-4y=8 like the other guy showed u we have to simplify that. So we get y= x-2 do the same table formula again an ill post my answers in a sec
I got (-1,-3) (0,-2) and (1,-1) I would show u a pic but I don't know how to
Hope I helped
Then u just graph the points in a graph, but make two different graphs for the two different equations.
Put both equations on one graph. The point where the lines cross is the solution of the system.
Ops yeah but them in the same graph I messed up! Sorry! :( @otonogold
Did it work?
Join our real-time social learning platform and learn together with your friends!