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Multiply x-1/4x+4 . x^2-2x-3/x^2+x-2 simplify your answer as much as you can
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\[\frac{ x-1 }{ 4x+4 }\times \frac{ x ^{2} -2x-3}{ x ^{2}+x-2 }\] What you do is just multiply the numerators together ontop and denominators together below. Do you get that?
ok
-7 on top
correct?
How did you get a constant?
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multiply the numbers on top
i got it
THanks
\[\frac{ (x-1)(x ^{2}-2x-3) }{ (4x+4)(x ^{2}+x-2) }\]
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