Question

Solve the equation.
3x^2+96=0

Answer 1

first do what you can do first to isolate the variable

Answer 2

get 96 on it's own side of the equals

Answer 3

96 +-96 +3x^2=0 +-96

Answer 4

pretty much, so what do you have now?

Answer 5

okay so this is what I have so far...\[3(x ^{2}+32)=0\]
=\[3\sqrt{x ^{2}} = \sqrt{32}\]
=\[x=\sqrt{8}\sqrt{4}\]
and I kept going and got x=4, but my teacher said it's wrong so if you could explain to me what I did wron that would be great.

Answer 6

you are REALLY over complicating this, just tell me what you have after the first step

Answer 7

3x^2=-96

Answer 8

ok, so what would you do next to isolate x?

Answer 9

dive 3 to both sides?

Answer 10

yep

Answer 11

to get what?

Answer 12

x^2=-32 & now I would Square root both sides correct?

Answer 13

yes, to get?

Answer 14

\[x=2i\sqrt{2}\]

Answer 15

that would appear correct if you simplified correctly. IF so, you're done.

Answer 16

wait I think I simplified it wrong...

Answer 17

\[x=2i\sqrt{2}\]