Mathematics
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OpenStudy (anonymous):
suppose y varies directly as x. write a direct equation that relates x and y. then solve. if y=45 whenx=15, find x when y=45
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OpenStudy (anonymous):
y = k * x
45 = k * 15 , what is k
OpenStudy (anonymous):
k =
OpenStudy (anonymous):
Is the answer 3
OpenStudy (anonymous):
k=3
OpenStudy (anonymous):
find x when y=45
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OpenStudy (anonymous):
y = k*x we know: k=3, y=45
45 = 3*x
the answer to this problem is what is the value of x
OpenStudy (anonymous):
The answer is y=3x correct
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Thanks can u help me on another 1
OpenStudy (anonymous):
second part of question:
"find x when y=45"
we can use our equation:
y=3x and set y to 45
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OpenStudy (anonymous):
Im confused
OpenStudy (anonymous):
Thanks can u help me on another 1
OpenStudy (anonymous):
sorry......
you did not solve the second part of the question
OpenStudy (anonymous):
do you know the answer to the second part ?
OpenStudy (anonymous):
No
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OpenStudy (anonymous):
y=3x
if y is 45, we have
45 = 3x
OpenStudy (anonymous):
so x must be 15........
that's answer to second question :)
OpenStudy (anonymous):
"write a direct equation that relates x and y."
y=3x
"find x when y=45"
x=15
OpenStudy (anonymous):
If y=-4 when x=2, find y when x=-6
OpenStudy (anonymous):
we must again make the equation
y = k*x
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OpenStudy (anonymous):
first, we have x and y -- find k
-4 = k * 2
OpenStudy (anonymous):
Is that part -2
OpenStudy (anonymous):
k=-2 :)
OpenStudy (anonymous):
so our equation is:
y = (-2) * x
we can use the equation to solve second part
find y when x=-6
OpenStudy (anonymous):
Is it 3
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OpenStudy (anonymous):
looks like it because of the way it is written
y=(-2) * (-6) <--- find y
OpenStudy (anonymous):
they had given us x, not y this time
OpenStudy (anonymous):
So is it 12
OpenStudy (anonymous):
yep :) answer is 12
OpenStudy (anonymous):
y is 12, when x=-6
our equation:
y = -2 * x
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OpenStudy (anonymous):
Okay thanks
OpenStudy (anonymous):
no problem
OpenStudy (anonymous):
If y =-9 when x=3, find y when x=-5
OpenStudy (anonymous):
Would it be y=(-3)×x would it be 15
OpenStudy (anonymous):
yes
and yes
completely right
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OpenStudy (anonymous):
If y=4 when x=16,find y when x=6
OpenStudy (anonymous):
well y is 1/4 of x, so k=1/4
if that is the constant, then y = 1/4 * 6
which is 6/4 or 1 2/4 or 1 1/2
OpenStudy (anonymous):
Okay would it be y=(.25)×x woukd it be 1.5
OpenStudy (anonymous):
yes, exactly
OpenStudy (anonymous):
If y=12 when x=18,find x when y=-16
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OpenStudy (anonymous):
now it starts to get difficult
y = k*x
12 = k*18
OpenStudy (anonymous):
to get k alone, we must divide both sides by 18:
12/18 = k
OpenStudy (anonymous):
.66
OpenStudy (anonymous):
yeah, k=0.66
OpenStudy (anonymous):
"find x if y=-16":
-16 = 0.66 * x
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OpenStudy (anonymous):
Would that be -24.24
OpenStudy (anonymous):
both sides multiplied by 100:
-1600 = 66 x divide both sides by 66
-1600/66 = x
x = -1600/66 = -24.24, yes
OpenStudy (anonymous):
Okay thanks :D ur amazing
OpenStudy (anonymous):
thanks :P
OpenStudy (anonymous):
I wish u could send pictures of the problem cause I dont know how to do it and it is a graph