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Solve the following system of equations. x + 3y + 2z = -16 2x - y + 2z = -15 2x - 2y - z = 1 Help?
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try subtracting eqn 1 by eqn 2 to eliminate z, and le the new equation will be eqn 4 then eqn 1 plus (eqn 3 multiply by 2) to eliminate z, and let this be eqn 5 then try elimination using eqns 4 and 5 to solve for x or y...
So would it be (-3, 5, -2)?
@Data_LG2
wait let me try
i got (-3, -1, -5)?
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I will tell you if that is correct I will retry just incase
In the meantime I think you are correct that was one of the answer choices. Thanks!!!
lol, np:) i did not mean to give you the answer ok? O.O
It's all on the down loooowww o____o
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