Parallel and Perpendicular Line assistance!
Write the equation of the line which passes through (5, –2) and is parallel to x = 4. (1 point) Write the equation of the line which passes through (2, 1) and is perpendicular to x = –2. (1 point) Write the equation of the line which passes through (–4, 2) and is parallel to y = –x + 6 in slope-intercept form. (2 point) Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form. (2 point)
what grade are you in?
My problem with these is that I flat out do not understand how to solve them. @PvtGunner I don't see where that comes into this question so I'd rather not answer.
1. x=5 2. y= 1/2x+5 3. y= -x-2 4. y= -1/4-11
@PvtGunner How did you solve it, show you work so I can understand it ;-;
1. if the equation of the line is x= 4, then it is a vertical line through all points with the x value of 4. to make a line parallel to this line, you would make a vertical line through all points with the x value 5, so it would be x=5. 2. when a line is perpendicular to another, the slope will be the opposite reciprocal (meaning it would be negative instead of positive, or vice versa and that the number's numerator and denominator would be switch, so -2 would become 1/2) and to find b, or the y-intercept, you would substitute the x and y values into the equation. so 1=1/2(2)+b, 1=1+b subtract 1 from both sides, making 0=b, making the equation y=1/2x (sorry, i realize i was wrong :P) 3. when a line is parallel to another line, the slope would be the same, therefore the slope of the new line is -1. you would again substitute in the x and y values, so 2=-1(-4)+b 2=4+b, subtract 4 from both sides, -2=b so the equation is y=-x-2
@PvtGunner Thanks! Close + Medal
@PvtGunner You didn't show how you solved 4 ;-;
hold on sorry
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