Question

h

Answer 1

\(\bf \textit{parabola "vertex form"}\implies y = a(x-h)^2+k\\ \quad \\
center = (h, k)\)

so if you plug the vertex coordinates given, what do you think it'd look like?

Answer 2

well... we only have the "h" and "k"... we dunno what "a" is

Answer 3

notice that \(\bf \textit{parabola "vertex form"}\implies y = a(x-h)^2+k\\ \quad \\
center = (h, k)\)

h k
vertex is at ( 5 , -3 )
x y

Answer 4

we find "a" by using the "other point" given, (6, 1) and plugging that in our equation and solving for "a"

Answer 5

well... dunno... what did you get for "a"?

Answer 6

hmmm the vertex is not a (6,1)
the vertex is at (5, -3)
thus \(\bf y = a(x-h)^2+k\implies y = a(x-5)^2-3\)

Answer 7

:)