Question

√y +10 = y-2

Answer 1

is y + 10 both inside the radical?

Answer 2

Yes, it is

Answer 3

√(y +10) = y-2 (square both side first, you will get)
y+10 = y^2-4y+4 (put everything into the left side of the equation)
-y^2-4y+y+10-4=0 (simplify)
-y^2-3y+6 =0 (divide the equation by -1, just to make it easier)
y^2+3y-6 =0 (you can't factor it, but you could use the square root formula)
Square root formula is: - b ± √(b^2-4ac)
a is a number which is times x^2
b is a number which is times x
c is a constant (number which is not a variable or times a variable and it is not a zero)
CAN you plug in the numbers into the simplified equation and solve, or still need explanations?