Question

p(x)=2x^4-6x+1 Is this an even or odd function or neither? I tried solving it and got p(-x)=2x+6x+1 but I'm not sure if it is odd or neither. Can someone explain this to me please?

Answer 1

you have all the data, just conclude :)

Answer 2

\(p(x)=2x^4-6x+1\)

\(p(-x)=2x^4+6x+1 \)

Answer 3

Since \(p(x) \ne p(-x)\), its not an even function

Answer 4

Since \(p(-x) \ne - p(x)\), its not an odd function either

Answer 5

So... ? :)

Answer 6

it's neither, thanks! :D

Answer 7

yu wlcme ! good job !!!

Answer 8

Thanks : )Can you help me with another problem that's similar to this one?

Answer 9

shoot

Answer 10

f(x)= 4^3sqrt -x ........ the 3 is in the tip of the sqrt I forget what that's called.

Answer 11

\(\huge f(x) = 4 \sqrt[3]{-x}\)

Answer 12

like that ?

Answer 13

or,

\(\huge f(x) = 4 ^\sqrt[3]{-x}\)

like this ?