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p(x)=2x^4-6x+1 Is this an even or odd function or neither? I tried solving it and got p(-x)=2x+6x+1 but I'm not sure if it is odd or neither. Can someone explain this to me please?
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you have all the data, just conclude :)
\(p(x)=2x^4-6x+1\) \(p(-x)=2x^4+6x+1 \)
Since \(p(x) \ne p(-x)\), its not an even function
Since \(p(-x) \ne - p(x)\), its not an odd function either
So... ? :)
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it's neither, thanks! :D
yu wlcme ! good job !!!
Thanks : )Can you help me with another problem that's similar to this one?
shoot
f(x)= 4^3sqrt -x ........ the 3 is in the tip of the sqrt I forget what that's called.
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\(\huge f(x) = 4 \sqrt[3]{-x}\)
like that ?
or, \(\huge f(x) = 4 ^\sqrt[3]{-x}\) like this ?
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