p(x)=2x^4-6x+1 Is this an even or odd function or neither? I tried solving it and got p(-x)=2x+6x+1 but I'm not sure if it is odd or neither. Can someone explain this to me please?

Question

ganeshie8 · Answer

you have all the data, just conclude :)

ganeshie8 · Answer

$p(x)=2x^4-6x+1$

$p(-x)=2x^4+6x+1 $

ganeshie8 · Answer

Since $p(x) \ne p(-x)$, its not an even function

ganeshie8 · Answer

Since $p(-x) \ne - p(x)$, its not an odd function either

ganeshie8 · Answer

So... ? :)

anonymous · Answer

it's neither, thanks! :D

ganeshie8 · Answer

yu wlcme ! good job !!!

anonymous · Answer

Thanks : )Can you help me with another problem that's similar to this one?

ganeshie8 · Answer

shoot

anonymous · Answer

f(x)= 4^3sqrt -x ........ the 3 is in the tip of the sqrt I forget what that's called.

ganeshie8 · Answer

$\huge   f(x) =   4 \sqrt[3]{-x}$

ganeshie8 · Answer

like that ?

ganeshie8 · Answer

or,

$\huge   f(x) =   4 ^\sqrt[3]{-x}$

like this ?