Question

How to factor 5n2+41n+42
(Five "n" squared + 41n +42)

Answer 1

well the method I use is multiply the coefficient of the leading term by the constant

5 x 42 = 210.

now find the factors of 210 that add to 41

thats the 1st step

Answer 2

Okay thanks

Answer 3

so when you get the factors of 210, one is 6

write it as the product of 2 binomials

\[\frac{(5n + factor 1)(5n + factor2)}{5}\]

check the binomials for common factors...that will cancel with the denominator.

this leaves the factored form

Answer 4

Okay thanks! I'm going to try it and see what I get