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Trigonometry question!
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Find the following value for θ such that 0≤ θ<2π cos θ = -1/2
So it's either in the second or third quadrant, and it's a 45-45-90 triangle
For this question, you need to look at a unit circle to figure it out. When is cosine -1/2 in the second quadrant?
Also, your profile picture rocks :3
I got 120 degrees, but i dont really know how to get there...
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Okay, so when cosine is -1/2, you look at your unit circle and you can see that at 120 degrees, the coordinates are (-1/2, \[\sqrt{3}\]/2). The x value is cosine, and the y value is sine.
i just guessed and checked (thanks! :^) )
You're totally welcome!
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