Question

(-2, 2/3) U (2/3, 10/3
Does anyone know how to graph this on a line?

Answer 1

Bracket at the end of the expression is missing. It is important to know the type of bracket before graphing.

Answer 2

What's u in between them

Answer 3

0< I3x-2I <8 was the inequality and then the interval notation is what i wrote above

Answer 4

those are supposed to be absolute brackets in the equation not 1's

Answer 5

I'm supposed to graph the intervals on a line and i dont know how

Answer 6

I would solve the inequality as follows.
First Consider the LHS of the inequality, 0 < | 3x-2 |
When opening the 'mod' sign, we get two inequalities : 0 < 3x -2 and 0 > - (3x-2)
ON solving both of these sub-inequalities, we get the same solution i.e.
x > 2/3 ...................... (1)

Now, RHS of the inequality is | 3x-2 | < 8
When opening the 'mod' sign, we get two inequalities : (3x-2) < 8 and -(3X-2) > 8
ON solving both of these sub-inequalities, we get
X < 10/3 .....................(2) and
x < -2 .......................(3)

We neglect inequality (3) because the range of values represented in (3) is already included in (2).

Therefore , we need to graph the range of x using two inequalities (1) and (2).