Question

Which of the following equations have the same solution? Solve all three equations separately and explain each step.

I. 2x + 4 = 3x – 11
II. 3x + 3 = 51
III. the quantity of 2x plus 1, divided by 3 equals the quantity of x plus 6, divided by 2

Answer 1

2x + 4 = 3x – 11
3x + 3 = 51
2x + 1/ 3 = x + 6 / 2

Answer 2

@ganeshie8

Answer 3

Start by solving first equation

Answer 4

2x + 4 = 3x - 11

Answer 5

add 11 to both sides?

Answer 6

wait no, subtract 4 first i think

Answer 7

```
I. 2x + 4 = 3x – 11
```
yeah u can subtract 4 both sides. wat do u get

Answer 8

2x + 4 = 3x - 11
-4 -4
2x = 3x - 7

Answer 9

next, subtract 3x both sides

Answer 10

wait a sec

Answer 11

2x + 4 = 3x - 11
-4 -4

2x = 3x - 15

Answer 12

2x + 4 = 3x - 11
-4 -4
2x = 3x - 7
-3x -3x

-1x = 7

Answer 13

u shud get that,
-11-4 = -15

Answer 14

alright -1x = 15

Answer 15

2x + 4 = 3x - 11
-4 -4

2x = 3x - 15
-3x -3x


-x = -15

x = 15

Answer 16

thats the solution for first equation

Answer 17

-1x = -15
/-1 /-1

x = 15?

Answer 18

yup, and u need to explain each step.
just add lines after each step, saying things like :- subtract 4 both sides... etc

Answer 19

alright gimme 1 sec to write this down :)

Answer 20

alright number 2, 3x + 3 = 51

Answer 21

I figured out 2, just need help on 3

Answer 22

2 is x = 16?

Answer 23

for equation 2 :-
```
3x + 3 = 51
```

subtract 3 both sides

3x = 48

divide 3 both sides

x = 16

Answer 24

yep thats what I did :D

Answer 25

for equation 3 :-
```
III. the quantity of 2x plus 1, divided by 3 equals the quantity of x plus 6, divided by 2
```

\(\large \frac{2x+1}{3} = \frac{x+6}{2}\)


cross multiply

2(2x+1) = 3(x+6)

distribute

4x + 2 = 3x +18

subtract 3x both sides

x + 2 = 18

subtract 2 both sides

x = 16