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Simplify+ find the domain? root(3x-5) * root(3x-5) - (2x+1)
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could you simplify ?
how would you do that
\[\sqrt{3x-5} \times \sqrt{3x-5} - (2x+1)\]
use this , \(\sqrt{stuff}\sqrt{stuff}=stuff\)
so, \(\sqrt{3x-5} \times \sqrt{3x-5} =...?\)
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ohhh so its 3x-5 - 2x+1
3x-5 - (2x+1) actually so, 3x-5 - 2x-1 =... ?
x-6!
Oh I did not know the two roots makes zero oh x_x
thnx!
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what about the domain ?
and 2 roots doesn't make a "zero" actually , \(\large \sqrt x\sqrt x = x^{0.5}x^{0.5}=x^{0.5+0.5}=x^1=x\)
ohhh I see thanks
and domain ?
x is greater than or equal to 3/5?
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3/5 or 5/3 ?
\(3x-5\ge 0 \\ 3x \ge 5 \\x \ge 5/3\)
oh sorry ment 5/3
then you are correct! good work! :)
thnx!!!
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welcome ^_^
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