Question

"Find the vertex of the graph of the function"
f(x)=(x+6)^2-5

Answer 1

Can you simplify it into f(x)=Ax+By+C form?

Answer 2

*Ax^2+Bx+C, I was thinking of standard form for some reason

Answer 3

how would that be finding the vertex

Answer 4

?

Answer 5

the equation is already in the vertex form for parabolas
therefore the vertex of your equation of f(x)=(x+6)^2-5
is (-6, 5)
because when f(x)=a(x-h)^2-k, (h, k) is the vertex
hope this helped :)