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Solve for x: the square root of x squared minus x minus 5 is equal to 5
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Square root both sides
so it would be x-x-5=25?
\[x^2-x-5=25\]
ohh yeah so i factor it and x would equal -5 and 6 right
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now test each root in the original equation... sometimes you have to toss one of them
i toss of the negative right @phi
I think both roots work. for x=-5 we have \[ \sqrt{(-5)^2 -(-5) - 5} \\ \sqrt{25 +5 - 5} \\ \sqrt{25}\\ 5 \] which is ok
ohh ok thank you :)
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