davids chance of winning is 1/3. If he plays five times what is the probability that he will once?
1/3, the probability, means that for every 3 games he plays he will win 1. If he plays 5, what do you do?
5 wins?
Well he will win once every 3 games he plays. If he plays 5, he definitely will win 1 already, no?
yeah...because 5 is too big for another win
What do you mean by too big?
if every 3 games means 1 win then if you have 5 games you can't have another win...
so then can you only have 1 true win?
Probability-wise, yes you have to play one more game to win another. But you have at least one win here so what is the probability of a 'yes'?
but I don't get what your trying to say...I want to know the probability of him winning once...all the things we have done so far don't lead me any where...
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