Geometry help?
I'll try
What is the line of reflection between pentagons PQRST and P'Q'R'S'T'? x = 1 ^ would it be this answer? y = x x = 0 y = 0
x - axsis is looking like the answer for it
First, see that X-axis is in between both d pentagons.
I see that..
good :) see that its exactly in mid of both pentagons
Yea I'll leave it to ganshie8 he is a pro :p
I don't know how to explain, I could only give answer so he'll take care of you :)
all points of both pentagons are at SAME distance from X-axis, so x-axis is the line of reflection.
@iNeedSeriousHelp was my answer right or wrong, though?
wrong I think... but we'll see what ganeshie8 says
@iNeedSeriousHelp go ahead explain :) idk how to explain well to... i just try thats all :)
I don't know how to explain, I can only say what I THINK is the answer...
its okay :) as i said, x-axis is the reflection line.
is it y=x?
equation of x-axis is : y=0
ok another question then. If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'? (-4, 5) ^ would this be the answer? (-2, 5) (4, -3) (4, -5)
nope
y=1 is a horizontal line, when u reflect something across horizontal line, x-coordinate WILL NOT change.
so X' wud be (4, something)
(4, -5) ?
Answer : (4, -3)
what omg
i see that you're just guessing :) these things are really easy once u start *seeing* them i guess lol
oh wait, i see why u said (4, -5). (4, -5) is correct IF the line of reflection is x-axis
but since line of reflection is y=1, the answer wud be (4, -3)
|dw:1381216888409:dw| that's where i'm confused. that's how i got the (4, -5 )
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