I need help ... How to write an equation of a trend line ?
take a quick screenshot of it and post it here
(-10, 3) (-5,1) (-1,-4) (3,-7) (12, -12)
\[Y=\frac{n\sum xy-\sum x\sum y}{n\sum xx-\sum x\sum x}(X-\bar X)+\bar Y\]
or, if you have a ti83 ... list1 = x parts list2 = y parts 2nd, stat, LineReg L1,L2
no 2nd, just stat, linereg
I don't get it -.-
it is labor intensive by hand ... an excel sheet helps
Oh my god I feel dumb
how are you spose to address this; by hand, by calculator, or by excel?
By hand
by hand will not be productive; but we can organize the data similar to an excel sheet
I just need to understand how to do it
stack the points, and multiply xy to the right of it; put x^2 to the left of it you will need to work with these columns
you need to organize something like this
the rest is just plugging into the equation
Okay ...
the hardest thing is the slope, it has the most parts n(sum xy) - sum x(sum y) ---------------------- n(sum xx) - sum x(sum x) 5(-196) - (-1)(-19) ------------------ 5(279) - (-1)(-1)
- 999 ------ 1394 which may or maynot reduce :)
take the average x and average y to build a point slope equation with: \[y=m(x-avgX)+avgY\] and that is the trendline equation
\[y = -\frac{999}{1394}(x+.2)-3.8\]
excel has a trendline feature, and it agrees with this process :)
Join our real-time social learning platform and learn together with your friends!