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Mathematics 13 Online
OpenStudy (anonymous):

I need help ... How to write an equation of a trend line ?

OpenStudy (jdoe0001):

take a quick screenshot of it and post it here

OpenStudy (anonymous):

(-10, 3) (-5,1) (-1,-4) (3,-7) (12, -12)

OpenStudy (amistre64):

\[Y=\frac{n\sum xy-\sum x\sum y}{n\sum xx-\sum x\sum x}(X-\bar X)+\bar Y\]

OpenStudy (amistre64):

or, if you have a ti83 ... list1 = x parts list2 = y parts 2nd, stat, LineReg L1,L2

OpenStudy (amistre64):

no 2nd, just stat, linereg

OpenStudy (anonymous):

I don't get it -.-

OpenStudy (amistre64):

it is labor intensive by hand ... an excel sheet helps

OpenStudy (anonymous):

Oh my god I feel dumb

OpenStudy (amistre64):

how are you spose to address this; by hand, by calculator, or by excel?

OpenStudy (anonymous):

By hand

OpenStudy (amistre64):

by hand will not be productive; but we can organize the data similar to an excel sheet

OpenStudy (anonymous):

I just need to understand how to do it

OpenStudy (amistre64):

stack the points, and multiply xy to the right of it; put x^2 to the left of it you will need to work with these columns

OpenStudy (amistre64):

you need to organize something like this

OpenStudy (amistre64):

the rest is just plugging into the equation

OpenStudy (anonymous):

Okay ...

OpenStudy (amistre64):

the hardest thing is the slope, it has the most parts n(sum xy) - sum x(sum y) ---------------------- n(sum xx) - sum x(sum x) 5(-196) - (-1)(-19) ------------------ 5(279) - (-1)(-1)

OpenStudy (amistre64):

- 999 ------ 1394 which may or maynot reduce :)

OpenStudy (amistre64):

take the average x and average y to build a point slope equation with: \[y=m(x-avgX)+avgY\] and that is the trendline equation

OpenStudy (amistre64):

\[y = -\frac{999}{1394}(x+.2)-3.8\]

OpenStudy (amistre64):

excel has a trendline feature, and it agrees with this process :)

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