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OpenStudy (erinweeks):
Havent done this in a while..
Write a formula for the general term (the nth term) of the geometric sequence.
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OpenStudy (erinweeks):
\[\frac{ 1 }{ 2 }, \frac{ 1 }{ -10 }, \frac{ 1 }{ 50 }, \frac{ 1 }{ -250 }\]
OpenStudy (erinweeks):
i so totally forgot how to do this !
OpenStudy (jack1):
bear with me... its been a while for me to
geom seq
\[a _{n} = a \times r ^{n-1}\]??? i think?
OpenStudy (erinweeks):
i dont even know lol .
OpenStudy (jack1):
a = ur initial
r = ur ratio or constant or whatever u call it
n = the term in the sequence you want
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OpenStudy (erinweeks):
n would be -5 ?
OpenStudy (jack1):
1 over -5...?
term 2 divided by term 1
OpenStudy (jack1):
so 1/-10 divided by 1/2 = 1/-5
OpenStudy (erinweeks):
or r would be -5
OpenStudy (erinweeks):
okay
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OpenStudy (jack1):
r = 1/-5...
n = whichever term we want
OpenStudy (jack1):
a = 1/2
... im pretty sure that's all we need for the equation hey ;D
OpenStudy (erinweeks):
hold on im going to post the answers
OpenStudy (erinweeks):
\[A. a \eta = (\frac{ 1 }{ 2 }) n-1 \frac{ 3 }{ 5 }\]
OpenStudy (erinweeks):
B. |dw:1381299061991:dw|
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