Question

state the conjugate of 6+sqrt2 and then multiply them together

Answer 1

@jdoe0001 can you help me with this as well?

Answer 2

conjugate of a pair, is the same exact pair, with a different sign in the middle

so \(\bf a + b\), it's conjugate is \(\bf a - b\)
\(\bf something - other\) conjugate is \(\bf something + other\)

and so on, pretty much the same thing, if it has a + first, the conjugate will use the -
if it has the - first, the conjugate will use the +

Answer 3

so its 6-sqrt2?

Answer 4

yes
\(\bf 6+\sqrt{2}\qquad conjugate \implies 6-\sqrt{2}\\ \quad \\
\textit{now, conjugates multiplication ends up like}\qquad (a-b)(a+b) = a^2-b^2\\ \quad \\
thus\\ \quad \\
(6+\sqrt{2})(6-\sqrt{2})\implies 6^2-(\sqrt{2})^2\implies 6^2-\sqrt{2^2}\)

Answer 5

okay, okay! Thanks, thats pretty easy

Answer 6

yw