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Algebra 15 Online
OpenStudy (anonymous):

Simplify. ∜400/∜5

OpenStudy (mathstudent55):

This rule may be helpful to get started: \( \dfrac{\sqrt[n]{a}} {\sqrt[n]{b}} = \sqrt[n]{\dfrac{a}{b} } \)

OpenStudy (anonymous):

yea but i got these A. 5∜2 B. 2∜5 C. 2√5 D. ∜80

OpenStudy (anonymous):

@mathstudent55

OpenStudy (mathstudent55):

Try my suggestion first. It won't give you the fianl answer, but it'll get you started. Then we can work on the next step.

OpenStudy (mathstudent55):

\( \dfrac{\sqrt[4]{400}} {\sqrt[4]{8}} = \sqrt[4]{\dfrac{400}{8} } \) Now divide 400 by 8, what do you get?

OpenStudy (anonymous):

i gott 50 @mathstudent55

OpenStudy (mathstudent55):

Sorry. It's 400 divided by 5, not 8. Let me do it again.

OpenStudy (anonymous):

its 80

OpenStudy (mathstudent55):

Right. \(\dfrac{\sqrt[4]{400}} {\sqrt[4]{5}} = \sqrt[4]{\dfrac{400}{5}} = \sqrt[4]{80} \)

OpenStudy (anonymous):

THANKS

OpenStudy (mathstudent55):

Now we need to simplify \( \sqrt[4]{80} \) We need to find the prime factors of 80. \(80 = 2 \times 2 \times 2 \times 2 \times 5 = 2^4 \times 5\) \(\sqrt[4]{80} =\sqrt[4]{2^4 \times 5} \) \(= \sqrt[4]{2^4} \times \sqrt[4]{5}\) \(= 2\sqrt[4]{5} \)

OpenStudy (anonymous):

GOTT THANKS

OpenStudy (mathstudent55):

wlcm

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