Question

The sum of four times a number and six times a second number is 36. The difference of five times the second number and three times the first number is 49. Find the numbers.. Please help!!

Answer 1

first number:x
second: y

sum of four times a number (so... 4x) and six times a second number (sooo 6y) is 36
this means
4x+6y = 36

Answer 2

difference of five times the second number (5y) and three times the first number (3x) is 49
difference means subtraction, so
5y - 3x = 49

now you have two equations

4x + 6y = 36
5y - 3x = 49

Answer 3

4x + 6y = 36
5y - 3x = 49

Answer 4

Thank you so much!

Answer 5

How do you solve it?

Answer 6

4x + 6y = 36
-3x +5y = 49

Using either elimination, or substitution... elimination is easier

multiply the whole second equation by 4, and the whole first by 3:

3*4x + 3*6y = 3*36
4*-3x +4*5y = 4*49

now you can add them together...try it (simplify the multiplication first)

Answer 7

A) 4x + 6y = 36
B) -3x +5y = 49

Multiply B) by 4/3
-4x + 20/3 y = 65.3333 then Add this to A
4 x + 6y = 36
20/3 y + 6y = 101.3333
12.6666 y = 101.3333
y = 8

4x + 48 = 36
4x = -12
x = -3

Answer 8

Perfect, thank you!

Answer 9

u r welcome